Table of Contents
What is the mole of nicotine?
162.1 g/mol
The molar mass of nicotine is 162.1 g/mol.
What is the mass of nicotine?
162.23 g/molNicotine / Molar mass
What is molecular formula of nicotine?
C₁₀H₁₄N₂Nicotine / Formula
How many grams of nitrogen are in nicotine?
17.3 %
It contains 74 % carbon, 8.7 % hydrogen and 17.3 % nitrogen….
| C | 12 |
|---|---|
| H | 1 |
| N | 14 |
| Atomic Mass |
How many moles of nicotine are in a cigarette?
1 Answer. 2.38⋅10−4 moles of nicotine.
What molecules are in nicotine?
Nicotine is an unusual alkaloid in that it has two nitrogen-containing heterocycles, pyridine and pyrrolidine. It is, of course, the tobacco component that makes smoking highly addictive, leading to the consequence that long-term smoking causes cancer.
What type of bond is nicotine?
The nicotine molecule contains a total of 27 bond(s) There are 13 non-H bond(s), 6 multiple bond(s), 1 rotatable bond(s), 6 aromatic bond(s), 1 five-membered ring(s), 1 six-membered ring(s), 1 tertiary amine(s) (aliphatic), 1 Pyrrolidine(s) and 1 Pyridine(s).
What is the molar mass of nicotine c10h14n2?
162.23 g/molAnabasine / Molar mass
How many single bonds are in nicotine?
10 Medium connectors (single covalent bonds)
What is the molar mass and formula weight of nicotine c10h14n2 the toxic and addictive stimulant in tobacco?
3.1Computed Properties
| Property Name | Property Value |
|---|---|
| Molecular Weight | 162.23 |
| XLogP3 | 1.2 |
| Hydrogen Bond Donor Count | 0 |
| Hydrogen Bond Acceptor Count | 2 |
What is the molecular formula of nicotine?
It tells that in one molecule of nicotine there are 5 atoms of carbon for each 7 atoms hydrogen and 1 atom of nitrogen. C10H14N2 is the molecular formula of nicotine. What is the formula mass of nicotine?
What is the molecular mass of nicotine?
The molar mass of C10H14N2 (Nicotine) is: 162.236 grams/mol. See also our theoretical yield calculator for chemical reactions (probably your next stop to finish the problem set).
What are the empirical and molecular formulas of nicotine?
empirical formula is C 4 H 5 N 2 O; 49.5% x 195 / 12 = 8.0 mol carbon (2x amount in empirical calculations) molecular formula is C 8 H 10 N 4 O 2; Find empirical/molecular formula for nicotine (contains carbon, hydrogen, nitrogen) if 5.250 mg nicotine combusted to form 14.242 mg CO 2 and 4.083 mg H 2 O. It has a molar mass of 160 g. 14.242 + 4.083 – 5.250 = 13.075 mg O 2 used ; 12 / (12 + 2 x 16) = 27% C in CO 2
What is the density of nicotine?
The molarity of (-)-Nicotine is 6.23 M based on a 100% pure compound with a density at 20 °C equal to 1.010 g/mL. If you multiply this density by 1000, you obtain g/L. If you divide g/L by the molecular weight of (-)-Nicotine which is 162.2 g/mole, you get moles per L which is molarity. [1.010 x 1000]/162.2 = 6.23 M.