Is Maharashtra CET Result Declared?

Is Maharashtra CET Result Declared?

MHT CET results 2021: State Common Entrance Test Cell, Maharashtra announced MHT CET results 2021 on Wednesday, October 27. Candidates who have appeared in the Maharashtra Common Entrance Test 2021, can check their result on the official website of MAHACET at mhtcet2021.mahacet.org.

How is MHT CET score calculated?

Candidates may check the formula to be followed by authorities: MHT CET Percentile Score = 100 * (Number of candidates in exam with normalized marks ≤ the candidate) ÷ Total number of candidates in the exam.

Who scored highest marks in CET?

The authorities will first declare the MHT CET result 2022 followed by the toppers list….MHT CET Toppers 2022.

Candidate name City Percentile Score
AYMAN FATEMA MOHD AMJADULLAH Nanded 100.0000000
AINWALE ANIRUDDHA ARUNRAO Nanded 100.0000000
RAJVEER LAKHANI Mumbai Suburban 100.0000000
KALYANI KUDALKAR Mumbai Suburban 100.0000000

Is CET 2021 result Declared?

However, as per past year trends, KCET 2022 result is expected this week. The result of KCET 2022 will be available on the KEA UGCET official website – kea.kar.nic.in result 2022….KCET 2021 result.

KCET 2021 Statistics
Number of candidates who appeared for the exam 1,93,447

Is 70 percentile good in MHT CET?

It is expected that the candidates with percentile 70 or above in the MHT CET 2021 will be awarded a rank 40,000 or above. Your marks could be around 60s-70s as per past year analysis. As per the MHT CET 2020 results, a score between 165 (Highest) and 149 was equivalent to 100 – 99.99 percentile.

How can I check MHT CET result 2021?

The respective board of MHT CET 2021 declared the MHT CET Result 2021 on 27th October 2021. The announcement of the result is made available on the official website. So you have to be ready with complete login details and visit the website mhtcet2021.mahacet.org to get your result.

Is 90 marks good in MHT CET?

Well, if you really 90 let me be honest it is not a very good score. Now regarding the colleges, with a score of 90 a government engineering college admission is not possible. But you can always try in a private engineering college. An individual can get a Government engineering college if the score is around 150 -170.

Is 75 marks good in MHT CET?

Hello dear, You have got 75 marks in mht cet exam. With the mentioned marks your expected percentile will be in between 80 to 90 and your rank will be in between the range of 19,001 to 30,000 as per the previous year analysis.

Can I get Government College with 85 percentile in MHT CET?

You score 85 percentile in MHT CET. In my opinion you secured the good percentile in MHT CET. You can get an admission in best college & branch. Most of the students want to join in the government college only because government college certificate has more value comparing to others.

Is 82 percentile good in MHT CET?

82 percentile in MHTCET means you can accept a general rank in the range of 27000 to 33000. Now this is not your actual rank rather it is assumption based on MHTCET Percentile vs rank statistics.

How to check MHT CET result 2022?

Candidates have to enter their login ID and password. Also, enter the captcha code and log in. The MHT CET result 2022 shall appear on the screen. Candidates may check all the details carefully and download the same. Video – How to check MHT CET result? How Much Should You Budget To Attend NEET Coaching In Kota For One Or Two Years? Read Here

What is the formula to calculate the percentage of MHT CET?

MHT CET Percentile Score = 100 * (Number of candidates in exam with normalized marks ≤ the candidate) ÷ Total number of candidates in the exam.

How many years is MHT CET score valid for?

Ans. MHT CET 2022 scores are valid for 1 year only. With this scorecard, you can take admission to the colleges of Maharashtra that accept MHT CET scores. Check MHT CET 2022 Participating Colleges

Is there any negative marking in MHT CET?

There is no negative marking and therefore, no marks will be deducted for incorrect attempts. MHT CET Score = (Number of Correct Attempts In Maths X 2) + (Number of Correct Attempts In Physics, Chemistry, Botany, Zoology X 1)