How many registers for 6800?

How many registers for 6800?

The 6800 had two 8-bit accumulators, a 16-bit index register, and a 16-bit stack pointer.

Can assembly language Programme written for 8085 be executed on Motorola 6800 microprocessor?

E.g. assembly language of 8085 is different than that of Motorola 6800 microprocessors. The microprocessor cannot understand a program written in Assembly language.

Which machine code is used to end the assembly language program?

END directive − It indicates the end of the source (asm) file. The END directive is the last line of the program; anything after the END directive is ignored by the assembler.

Which is the first microprocessor by Motorola?

The Motorola 68000 (sometimes shortened to Motorola 68k or m68k and usually pronounced “sixty-eight-thousand”) is a 16/32-bit complex instruction set computer (CISC) microprocessor, introduced in 1979 by Motorola Semiconductor Products Sector.

What is the meaning of ORG $1000 when writing the code?

ORG $1000: this tells the assembler that this program will be located and organized in memory at address $1000. START: this is the first instruction of the program, it is also considered a subroutine.

What is the clock frequency of z80?

Zilog Z80

General information
Max. CPU clock rate 2.5, 4, 6, 8 MHz to 10 MHz with CMOS variant up to 20 MHz and binary compatible derivatives (from Zilog) up to 33 and 50 MHz.
Data width 8 bits
Address width 16 bits
Physical specifications

What is assembly language program in 8085?

Problem – Write an assembly language program to add two 8 bit numbers stored at address 2050 and address 2051 in 8085 microprocessor….Program –

Memory Address Mnemonics Comment
200B ADC A A←A+A+carry
200C MOV H, A H←A
200D SHLD 3050 H→3051, L→3050
2010 HLT

What is assembly language microprocessor?

An assembly language is a low-level programming language for microprocessors and other programmable devices. It is not just a single language, but rather a group of languages. An assembly language implements a symbolic representation of the machine code needed to program a given CPU architecture.

How many bits does an MC6800 family have?

8-bit
How many bits does an MC6800 family have? Explanation: MC6800 is an 8-bit processor proposed by Motorola.

Why do we always write program starting with Org 0000?

ORG means origin ORG is used for specific addressing in microprocessor and microcontroller programming. This means we want to start our program from the 0000H address.

What does .org mean in assembly?

ORG (abbr. for ORiGin) is an assembly directive (not an instruction). It defines where the machine code (translated assembly program) is to place in memory.

How do you write assembly language program?

In assembly language, we use symbolic names to denote addresses and data. A number of such examples are dealt with in the successive chapters. Thus writing a program in assembly language has advantages over writing the same in a machine language. Assembly language programs are platform dependent.

What are the types of assembly language?

Assembly language has four types:

  • RISC (Reduced Instruction-Set Computer)
  • DSP (Digital Signal Processor)
  • CISC: Complex Instruction Set Computer.
  • VLIW: Very Long Instruction Word.

What is assembly language code?

An assembly language is a type of low-level programming language that is intended to communicate directly with a computer’s hardware. Unlike machine language, which consists of binary and hexadecimal characters, assembly languages are designed to be readable by humans.

What are sections in assembly?

An assembly program can be divided into three sections − The data section, The bss section, and The text section.

How does memcpy work in the 6800 assembly language?

The following 6800 assembly language source code is for a subroutine named memcpy that copies a block of data bytes of a given size from one location to another. The data block is copied one byte at a time, from lowest address to highest.

What is the architecture of a 6800?

The 6800 architecture was a TTL-compatible LSI design modeled after the DEC PDP-11 processor. The 6800 had an 8-bit bidirectional data bus, a 16-bit address bus that could address 64 KB of memory, and came in a 40-pin DIP package.

How many opcodes are in a 6800 microcontroller?

The 6800 has a 16-bit address bus that can directly access 64 KB of memory and an 8-bit bi-directional data bus. It has 72 instructions with seven addressing modes for a total of 197 opcodes.

What does 6800 stand for?

The 6800 (“sixty-eight hundred”) is an 8-bit microprocessor designed and first manufactured by Motorola in 1974.